Truss Member Forces

Tool 15 · Statics · EN 1990

Truss Member Forces

Pratt, Howe and Warren trusses solved with the direct stiffness method — every member force in tension or compression, the support reactions, zero-force members and the deflected shape, worked step by step.

Truss & loads

P is applied downward at every intermediate lower-chord joint.

Member forces in a determinate truss do not depend on E and A — only the deflections do.

40.064.072.072.064.040.0-40.0-64.0-64.0-40.050.030.020.030.050.0-64.0-38.4-12.8-12.8-38.4-64.020.020.020.020.020.0RA = 50.0 kNRG = 50.0 kNABCDEFG12345

Blue = tension · red = compression · dashed = deflected shape ×153

RA

50.00 kN

RB

50.00 kN

Max tension

72.0 kN

C–D

Max compression

-64.0 kN

A–1

δmax

3.9 mm

joint deflection

Member forces
MemberLength (m)N (kN)State
A–B2.0040.00Tension
B–C2.0064.00Tension
C–D2.0072.00Tension
D–E2.0072.00Tension
E–F2.0064.00Tension
F–G2.0040.00Tension
1–22.00-40.00Compression
2–32.00-64.00Compression
3–42.00-64.00Compression
4–52.00-40.00Compression
B–12.5050.00Tension
C–22.5030.00Tension
D–32.5020.00Tension
E–42.5030.00Tension
F–52.5050.00Tension
A–13.20-64.03Compression
B–23.20-38.42Compression
C–33.20-12.81Compression
E–33.20-12.81Compression
F–43.20-38.42Compression
G–53.20-64.03Compression

Sign in to see the full calculation

Your inputs are saved — pick up right where you left off.

ArchiStructura — Eurocode Student Toolkit

Based on EN 1990, EN 1991, EN 1992-1-1, EN 1993-1-1, EN 1995-1-1 & EN 1997-1.
Educational tool only — always verify against the National Annex and a qualified engineer. The full Eurocodes are published by your national standards body.